Skip to main content

Worksheet-5-Knowing our Numbers-Large Numbers- Class 5 and Class 6

Worksheet-5-Knowing our Numbers-Large Numbers- Class 5 and Class 6




1.       
What is the difference between the greatest and the least number that can be written using the digits 6,2,7,4,3 each only once

a)
50000
b)
52965

c)
52865
d)
51965
2.       
The smallest 6-digit digit number is called

a)
One lakh
b)
One crore

c)
Ten lakh
d)
Ten crore
3.       
Write the numeral for the number ‘ five lakh forty one.

a)
50,00,041
b)
5,00,041

c)
500,041
d)
50,041
4.       
1 lakh = _______ thousands

a)
1
b)
10

c)
100
d)
1000
5.       
The place value of 8 in 5,82,009 is  _________ .

a)
Eight thousand
b)
10,000

c)
Eighty thousand
d)
8,00,000
6.       
The largest 6-digit number is _______ .

a)
999999
b)
99999

c)
100000
d)
99999999
7.       
If you add 1 to the largest 5-digit number , it will become _________ .

a)
999999
b)
99999

c)
100000
d)
999999
8.       
There are  _________ 3-digit numbers.

a)
100
b)
899

c)
980
d)
900
9.       
The number 5,56,984 according to Indian place value system will be

a)
Fifty thousand six hundred eighty-four
b)
Five lakh fifty-six thousand nine hundred eighty-four

c)
Five lakh fifty-six thousand eight hundred ninty-four
d)
None of these
10.   
What is the predecessor of the smallest 5-digit number?

a)
99998
b)
99990

c)
9999
d)
None of these
11.   
The successor of the largest 4-digit number is _____________.

a)
(i) 99,999                                                  
b)
1,00,000
c)
(iii) 10,000                                                
d)
10,00,000
12.   
The number one less than 50000 is _________ .

a)
9999
b)
40999
c)
99950
d)
49999
13.   
How many zeroes are there in one lakh?

a)
four
b)
five

c)
six
d)
seven
14.   
70,000+500+30+9 = ________

a)
705039
b)
70539

c)
75039
d)
None of these
15.

Write the number name of the following numbers.

a)
3,45,607-



b)
56,899-



c)
1,00,004-



d)
5,55,667-



Comments

Popular posts from this blog

NCERT Solutions for Class 6 Chapter 10: Mensuration

  NCERT Solutions for Class 6 Chapter 10: Mensuration Exercise 10.1 Page no: 212 1. Find the perimeter of each of the following figures: Solutions: (a)  Perimeter = Sum of all the sides = 1 + 2 + 4 + 5 = 12 cm (b) Perimeter = Sum of all the sides = 23 + 35 + 35 + 40 = 133 cm (c) Perimeter = Sum of all the sides = 15 + 15 + 15 + 15 = 60 cm (d) Perimeter = Sum of all the sides = 4 + 4 + 4 + 4 + 4 =20 cm (e) Perimeter = Sum of all the sides = 1 + 4 + 0.5 + 2.5 + 2.5 + 0.5 + 4 = 15 cm (f) Perimeter = Sum of all the sides = 4 + 1 + 3 + 2 + 3 + 4 + 1 + 3 + 2 + 3 + 4 + 1 + 3 + 2 + 3 + 4 + 1 + 3 + 2 + 3 = 52 cm 2. The lid of a rectangular box of sides 40 cm by 10 cm is sealed all around with tape. What is the length of the tape required? Solutions: Length of required tape = Perimeter of rectangle = 2 (Length + Breadth) = 2 (40 + 10) = 2 (50) = 100 cm ∴ Required length of tape is 100 cm 3. A table top measures 2 m 25 cm by 1 m 50 cm. What is the perimeter of the table top? Solutions: L...

NCERT Solutions for Class 6 Chapter 3: Playing With Numbers

  NCERT Solutions for Class 6 Chapter 3: Playing With Numbers Exercise 3.1 page no: 50 1. Write all the factors of the following numbers: (a) 24 (b) 15 (c) 21 (d) 27 (e) 12 (f) 20 (g) 18 (h) 23 (i) 36 Solutions: (a) 24 24 = 1 × 24 24 = 2 × 12 24 = 3 × 8 24 = 4 × 6 24 = 6 × 4 Stop here since 4 and 6 have occurred earlier Hence, the factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24 (b) 15 15 = 1 × 15 15 = 3 × 5 15 = 5 × 3 Stop here since 3 and 5 have occurred earlier Hence, the factors of 15 are 1, 3, 5 and 15 (c) 21 21 = 1 × 21 21 = 3 × 7 21 = 7 × 3 Stop here since 3 and 7 have occurred earlier Hence, the factors of 21 are 1, 3, 7 and 21 (d) 27 27 = 1 × 27 27 = 3 × 9 27 = 9 × 3 Stop here since 3 and 9 have occurred earlier Hence, the factors of 27 are 1, 3, 9 and 27 (e) 12 12 = 1 × 12 12 = 2 × 6 12 = 3 × 4 12 = 4 × 3 Stop here since 3 and 4 have occurred earlier Hence, the factors of 12 are 1, 2, 3, 4, 6 and 12 (f) 20 20 = 1 × 20 20 = 2 × 10 20 = 4 × 5 20 = 5 × 4 Stop here since 4 and 5...

NCERT Solutions for Class 6 Chapter 12: Ratio and Proportion

  NCERT Solutions for Class 6 Chapter 12: Ratio and Proportion Exercise 12.1 page no: 251 1. There are 20 girls and 15 boys in a class. (a) What is the ratio of number of girls to the number boys? (b) What is the ratio of number of girls to the total number of students in the class? Solutions: Given Number of girls = 20 girls Number of boys = 15 boys Total number of students = 20 + 15 = 35 (a) Ratio of number of girls to number of boys = 20 / 15 = 4 / 3 (b) Ratio of number of girls to total number of students = 20 / 35 = 4 / 7 2. Out of 30 students in a class, 6 like football, 12 like cricket and remaining like tennis. Find the ratio of (a) Number of students liking football to number of students liking tennis. (b) Number of students liking cricket to total number of students. Solutions: Given Number of students who like football = 6 Number of students who like cricket = 12 Number of students who like tennis = 30 – 6 – 12 = 12 (a) Ratio of number of students liking football to the ...